ln(x+1)-ln(x-1)=2*ln(2^1/2)

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Solution for ln(x+1)-ln(x-1)=2*ln(2^1/2) equation:


D( x )

x+1 <= 0

x-1 <= 0

x+1 <= 0

x+1 <= 0

x+1 <= 0 // - 1

x <= -1

x-1 <= 0

x-1 <= 0

x-1 <= 0 // + 1

x <= 1

x in (1:+oo)

ln(x+1)-ln(x-1) = 2*ln((2^1)/2) // - 2*ln((2^1)/2)

ln(x+1)-ln(x-1)-(2*ln((2^1)/2)) = 0

ln(x+1)-ln(x-1)-2*ln(2/2) = 0

ln(1*(x+1))-ln(x-1) = 0

ln((1*(x+1))/(x-1)) = 0

ln((x+1)/(x-1)) = 0

ln((x+1)/(x-1)) = ln(e^0)

(x+1)/(x-1) = e^0

(x+1)/(x-1)-e^0 = 0

(x+1)/(x-1)-1 = 0

(x+1)/(x-1)+(-1*(x-1))/(x-1) = 0

x-1*(x-1)+1 = 0

2 = 0

2/(x-1) = 0

2/(x-1) = 0 // * x-1

2 = 0

x belongs to the empty set

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